Closed

Clone mobile app iOS and android and website

8 freelancers are bidding on average $375 for this job

ProgetTechnology

Hi, I have read carefully about your requirements. I am a full time developer and I have best skills and much experiences in mobile app developing (Android and iOS) I am sure complete this project. If you award thi More

$250 AUD in 8 days
(13 Reviews)
6.7
vipinjain1213

Hello, I have gone through the job description and perceived that you are seeking a well experienced mobile app developer in order to design and develop your app. I am a full time developer and I have best skills and More

$200 AUD in 10 days
(8 Reviews)
4.3
maxpl

Dear Sir, I am an expert mobile and web developer by profession. I have developed many apps for 7+ years and uploade More

$200 AUD in 7 days
(3 Reviews)
4.5
rvtechsolution

Hi Hello there, I'm a senior Mobile developer with 7+ years of experience in native APP development. we are ready to build Clone mobile app iOS and android and website Please share more details. Kindly initiate More

$140 AUD in 7 days
(13 Reviews)
2.3
techskills16

Hi I am a professional web and app developer I am expert in Wordpress,Django framework,PHP,Android,IOS,flutter,CSS,react native I did my MS CS from NUST Islamabad Please open message box for me so we can discuss the d More

$140 AUD in 7 days
(3 Reviews)
1.7
UmairAnjumHere

⭐⭐⭐⭐⭐ I am a Senior Mobile Developer. ⭐⭐⭐⭐⭐ I have more than 3 years of experience in Mobile development and I have worked on several similar projects I can work in Android (Java, Kotlin , Xml), IOS (Swift), React Nat More

$250 AUD in 7 days
(1 Review)
0.5
DanilaGi

Hello, Thanks for giving me a chance to submit a proposal. You’re looking for a mobile expert and this is exactly what I specialize in. Please have a look samples of my work on mobile:{ [login to view URL] More

$150 AUD in 7 days
(0 Reviews)
0.0
mab007

[login to view URL] Check my portfolio for more info. I have experience in ios and swift in e-commerce platform

$1667 AUD in 15 days
(0 Reviews)
0.0