Add a interstitial admob in a flashlight app

Cancelled Posted 5 years ago Paid on delivery
Cancelled Paid on delivery

Hi i want to add a interstitial ad in my flashlight [login to view URL] will be a button in my [login to view URL] user will click the button interstitial ad will show.

Advertisement Design Advertising Android HTML5 Mobile App Development

Project ID: #17595541

About the project

9 proposals Remote project Active 5 years ago

9 freelancers are bidding on average $33 for this job

ricky641b

Hey The interstitial ads that you want to show are from Google Ads or Admob? Do you have setup account for that? I will start the work immediately. I can do over teamviewer if you want.

$30 USD in 1 day
(52 Reviews)
5.9
uhoang19893

Hi there, I can help you to add the advertisement in your app and upload it to the App Store/Play Store. Please let me know when we can get it started. Thank you.

$50 USD in 1 day
(82 Reviews)
6.6
guddumehta

Greetings!! I can implement interestitial ads on your app right now. Please message me so that i can start working on it immediately. Thanks, Pragati

$25 USD in 1 day
(27 Reviews)
5.4
Harry1990

Client Requirement's : Add a interstitial ad-mob in a flashlight app ************************************************* ✪ ✪ MY BEST PAY IS YOUR SATISFACTION ✪ ✪

$23 USD in 1 day
(52 Reviews)
5.2
ownmyserver

Hello Friend, I have 4+ year experience in design and development of Websites and Mobile Applications. I have relevant experience to your requirement. I can do your project. I have expertise in developing Appointme More

$25 USD in 1 day
(19 Reviews)
5.0
HammadRasheed220

I am also looking for the simple task like this. Although I am a new freelancer but experienced in Android development.

$20 USD in 1 day
(23 Reviews)
4.5
jaybarochiya

Hello I would like to work with you I have experience working with web and Android Mobile Application Design. I have worked on a couple of projects based on this Application. if you interested then I will show More

$23 USD in 1 day
(1 Review)
0.0